In a right triangle, if one acute angle has measure 6x-10 and the other has measure 2x- 4 , find the larger of these two angles.

Question

In a right triangle, if one acute angle has measure 6x-10  and the other has measure  2x- 4 , find the larger of these two angles.

asadkarim7 · Answer

the equation would be 
(6x-10) + (2x-4) +90 = 180 
solve for x and then put the value of x in both angles to find which is bigger

safia21 · Answer

how do you solve for x

asadkarim7 · Answer

eliminate the braces in (above posted ) equation and on LHS keep the coefficient value

anonymous · Answer

You lift the parenthesizes: 
8x-14+90=180 ,
8x+76=180
Then you isolate the numbers and the x'es: 
8x=104
Then you divide by 8 to get x
x=13

asadkarim7 · Answer

like 6x -10 +2x -4 = 90 
6x +2x = 104
8x = 104
x = 13

safia21 · Answer

thanks can you guys help me with one more problem

asadkarim7 · Answer

sure

asadkarim7 · Answer

link me

safia21 · Answer

∆ABC if BC is one inch longer AB, AC  is 10 inches shorter than the sum of BC and and AB and the perimeter of ∆ABC is 72 inches find the length of BC

safia21 · Answer

http://openstudy.com/groups/mathematics?version=feed:get-live-help&referrer=mathematics&domain=www.freemathhelp.com#/groups/mathematics/updates/4e399c9d0b8bf47d065fd1c5 is the reply

asadkarim7 · Answer

oh k first assume the length of AB = x 
Bc would be = x+1 
Ac would be = ( x + x+1) -10
                   = (2x +1) -10 
                   = 2x -9
x + x+1 + 2x-9 = 72
2x +1 + 2x -9 =72
4x -8 =72
4x =80 
x = 20



so BC would be x + 1
x= 20 
so BC= 21