Question

find three consecutive intergers whose sum is 480

Answer 1

x+x+1+x+2=480
3x+3=480
3x=477
x=159
159,160,161r the no.s

Answer 2

Call one k. The other would be k+1, then the other would be k+2
Sum these:
\[k+k+1+k+2=3k+3=480\]
Subtract 3.
3k=477
k=159
That means you have 159, 160, 161

Answer 3

thank you!

Answer 4

uw