Question

Please help! At what value of x will the function g(x) have a hole?

g(x)=(x+5)(x-5)(x-3)
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(x+5)(x+3)

Answer 1

At what values will the denominator equal 0?

Answer 2

Since any number divided by zero is undefined you'll have a hole.

Answer 3

5
-5
3
-3
OR
0

Answer 4

when is x+5=0
when is x+3=0

Answer 5

Plug in -5 and (x+5) becomes 0. 0 tiems anything on the bottom will be 0.

Answer 6

The same principle applies to (x+3)

Answer 7

you have a vertical asymptote at x=-3

Answer 8

I don't understand. I just need one answer. :/ -5 or -3?

Answer 9

you have one answer