Question

Find AF:FC in the attached geometrical figure.

Answer 1

Can u do doc instead of docx or pdf...

Answer 2

ok

Answer 3

tks.

Answer 4

i believe the answer is 1:1 because ad:db=af:fc and ad:db=1:1.. n i can prove that

Answer 5

its a property i believe

Answer 6

estudier?/???

Answer 7

I just downloaded it, looking now....

Answer 8

i gotta go mkuma.. but i still believe it is right.. estudier will help you thiugh.. sorry..

Answer 9

thanks ...!

Answer 10

Do I have to show ABC is 90 first?

Answer 11

Or I can just assume?

Answer 12

Blasted censor!

Answer 13

ASSUME

Answer 14

We can't assume it....if we can get by some property then it is

Answer 15

OK, it is, I will include it..

Answer 16

Let GBC = theta = BED = DEA and

BDF/DBC are right.

So ADE/DEB are congruent 1,1,2 type triangles and

AD:DB is 1:1 and then as Ashkar says.