Question

find the equation in standard form which passes through (-2, 7) and (1,1)

Answer 1

can someone please attempt at helping me or solving this porblem

Answer 2

y-7/(7-1)=X+2/(-2-1)

Answer 3

(y-7)/(7-1)=(X+2)/(-2-1)

Answer 4

what is their definition of a "standard form"?

Answer 5

im not sure

Answer 6

ax+by=c

Answer 7

standard form is defined as ax+by=c ; but alot of times they use the terminology to mean slope intercept form ....

Answer 8

so its good to know which one they are refering to :)

Answer 9

2X+Y=3

Answer 10

yes slopeintercept form is what i think they are reffering to

Answer 11

subtract your points and stack the value of y over x like this: y/x to determine the slope

(-2, 7)
-(1, 1)
------
-3, 6 ; y/x = 6/-3, simplify to -2 right?

Answer 12

now we can use a modified form developed from the point slope form of a line like this:

y = mx -mPx +Py where m=slope; P(x,y) is either given point

Answer 13

y = mx -mPx +Py ; (1,1) looks simple enough to use
y = -2x --2(1) + 1

y = -2x +2 + 1

y = -2x +3

Answer 14

finding m=(1-7)/(1--2)
=-6/3
=-2

use: y=mx +c

we find c=11 when sub:(-2;7)

then y=2x+11

Answer 15

we can test this one:

y=2x+11 ; at (1,1)

1 = 2(1) + 11

1 = 2 + 11

1 = 13 .... aint it

Answer 16

chk it with mine we get:

y = -2x +3 ; (1,1)
1 = -2(1) + 3
1 = -2 + 3
1 = 1 ............. good

y = -2x +3 ; (-2,7)
7 = -2(-2) + 3
7 = 4 + 3
7 = 7 ........... good

Answer 17

y=.5x+.5

Answer 18

mz ... care to prove that result?

Answer 19

teen, do you see why my results are correct?

Answer 20

THANK YOU ALL.. i have been following along with your work and have came up with an answer I'm confident with.

Answer 21

y=mx+c
m=(7-1)/(-2-1)=-2
y=-2x+c
puttng 1,1
y=-2x+3


opppssss!!!!!

Answer 22

lol .... at least you proofed it ;)

Answer 23

sry@64