Question

The perimeter of a rectangle is 16 inches and its diagonal is sqrt(34) inches. Find its length and width.

length=

width=

Answer 1

hello jahtoday!

Answer 2

length = a
&
width = b

Answer 3

hey!

Answer 4

so 2a+2b=16 correct?

Answer 5

and

Answer 6

don't know the rest lol I am assuming pythagoreom

Answer 7

yes very good
the 2 side lengths are a and b and the hypotenuse is the diagonal of the rectangle

Answer 8

cool so a^2+b^2=16

Answer 9

then solve by system of solutions?

Answer 10

wait whats the length of the diagonal?

Answer 11

yeah mistype
sqrt34

Answer 12

ah because its sqrt the ^2 cancels it out

Answer 13

but in Pythagorean the a^2 +b^2=c^2
in this case c is the diagonal. so yes

Answer 14

thank u 4 the visual myiniaya

Answer 15

:)

Answer 16

so yes now that u have the right 2 equations u can solve by systems of solutions u mentioned before

Answer 17

I am going the route of a=8-b on the right track?

Answer 18

then substituting it in

Answer 19

k looks good

Answer 20

W=3, L=5

Answer 21

Thank you Zak but working there

Answer 22

I well come every one

Answer 23

so substituting it into b^2+8-b=34

Answer 24

L=3, W=5
or
L=5, W=3

Answer 25

changing into quadratic as b^2-b-26=0 but not thinking I am right

Answer 26

b^2+(8-b)^2=34

Answer 27

oh forgot the ^ thank you

Answer 28

jah is right

Answer 29

so should go to 2b^2-16b+30=0

Answer 30

b^2+64-16b+b^2=34

Answer 31

yup now u can factor or use the quadratic formula

Answer 32

remember however that these are measurements and measurements have to b positive