Question

Solve using the substitution method.

1/3x-1/5y= 7

1/6x+2/3= -4

Answer 1

i dont see why we need to be constrained to the substitution method ....

Answer 2

Solve the second equation for X and then plug that value in for the X in the first equation.

Answer 3

I'm assuming it wants the Y-value?

Answer 4

To use the substitution method, solve the second equation for x, then substitute the result in for x in the first equation and solve it for y.

Answer 5

just help plz

Answer 6

1/3x-1/5y= 7 ; *-1/2
1/6x+2/3y= -4

-1/6x+1/10y= -7/2
1/6x+2/3y= -4
------------------
y(1/10+2/3) = (-4 -7/2)

y = (-15/2)/(1/10+2/3) :)

Answer 7

Amistre, There is no Y in the second equation.

Answer 8

can u make it clear

Answer 9

it's pose to be a y

Answer 10

y = (-15/2)/(23/30)

y = -15(30)/2(23)
= -15(15)/(23)
= -225/23

if i kept the fraction in line

Answer 11

is the answer right

Answer 12

as far as i can tell; that would be the answer for y ... who conjured up this twisted problem?

Answer 13

What amistre did, was;

Mutiplied each side of the first equation by -1/2.
You then combine the first and second equations using addition, the x terms cancel and you're left with y = (-15/2)/(1/10+2/3) = -225/23

Answer 14

colving for x is just as much a pain even when you know the value of y

if you have only one option with a y=-225/23 id take it :)

Answer 15

http://www.wolframalpha.com/input/?i=1x%2F3-1y%2F5%3D+7+and++1x%2F6%2B2y%2F3%3D+-4+