An administrative assistant has 4 blue file folders, 3 red
folders, and 3 yellow folders on her desk. Each folder contains different
information, so two folders of the same color should be viewed as being
different. She puts the file folders randomly in a box to be taken to a
meeting. Find each probability.
1. P(4 blue, 3 red, 3 yellow, in that order)
2. P(first 2 blue, last 2 blue)
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OpenStudy (zarkon):
where are you stuck?
OpenStudy (anonymous):
all
OpenStudy (zarkon):
do you know how many ways you can arrange the 10 folders?
OpenStudy (anonymous):
1) 4!3!3! ?
OpenStudy (zarkon):
that is actually the numerator to the first problem :)
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OpenStudy (anonymous):
1) 4!3!3! M'I corect ?
OpenStudy (zarkon):
what is the denominator?
OpenStudy (anonymous):
10
OpenStudy (zarkon):
10!
OpenStudy (zarkon):
\[\frac{4!3!3!}{10!}\]
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OpenStudy (anonymous):
for frist one?
OpenStudy (zarkon):
yes
OpenStudy (anonymous):
how second?
OpenStudy (zarkon):
same experiment so 10! is still the denominator
OpenStudy (zarkon):
you have 4 choices for the first blue,3 for the second 2 for the second to last spot and 1 for the very last spot and 6! for the middle
so 4!6!
\[\frac{4!6!}{10!}\]
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