Question

f(x)=\[2x^3+x-4\]

Find the equation of the tangent line to f -1 (x) at the point where x = -22.

Answer 1

f(22) = f'(22)(22-a)

That should help you out a little bit

Answer 2

Plug in x=-22. Find the y value, which is the x value for f^(-1)(x)
Then plug in this "y" value into f'(x). There is the slope.
Then you have the points ("y",22).
Point slope form to find equation of line.

Answer 3

malevolence, what's wrong with my way?

Answer 4

Oh, nothing, I was just saying.

Answer 5

Thank you.

Answer 6

No problemmm :P