Question

Which is the center of the circle whose equation is (x - 3)2 + (y - 4)2 = 121?
(−3, 4)
(3, −4)
(−4, 3)
(3, 4)

Answer 1

3, 4

Answer 2

thanks, how did you get that ?

Answer 3

(x – h)^2 + (y – k)^2 = r^2

Answer 4

(x-a)^2+(y-b)^2= r^2 is the standard form of a circle with a,b as the centre and r as the radius!

Answer 5

use general formula
(x-a)^2 + (x-b)^2 = r^2
whre centre = (-a,-b)
just compare this with your expression and its easy

Answer 6

sorry! = (a,b) is the centre