Question

suppose z varies directly as the square of x and inversely as y. if z=8 when x=4 and y=6, find z when x=6 and y=12

Answer 1

\[\Huge z = \frac{kx^2}{y}\]

Answer 2

find k in the first step!

Answer 3

\[\large 8 = \frac{4(k)}{6}\]

Answer 4

can u do it now?

Answer 5

yea, thanks

Answer 6

welks!

Answer 7

\[Z=C*(x ^{2}/y)\]

8=C(16/6) FIND C

C=3

then
Z=3∗(x2/y)
Z=3∗(36/12)
Z=9