Question

which quadratic equation has a vertex of (0,5)

Answer 1

okay what are the equation

Answer 2

y=(x-5)^2
y=(x+5)^2
y=x^2-5
y=x^2+5

Answer 3

\[y = a(x-h)^{2} +k\]
vertex at (h,k)

Answer 4

so which equation is that

Answer 5

thats the general quadratic equation in vertex form.
they gave you a vertex --> h=0, k=5
which equation has h=0 and k=5 using the general form as a guide

Answer 6

y=(x+5)^2
?

Answer 7

almost, you have the right idea but vertex is (h,k) h is x_coordinate
h = 0 so it follows that (x-h)^2 is (x-0)^2 = x^2

Answer 8

y=(x-5)^2
?

Answer 9

ok look at general equation (a = 1)
--> (x-h)^2 + k
we know h=0 and k =5 from the vertex given (0,5)
plug it in
-->(x-0)^2 + 5

Answer 10

so it must be y=x^2+5

Answer 11

yes