Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (amistre64):
the same way youd use the lfio method or 22 other methods :)
OpenStudy (anonymous):
Get the items in the first set of parenthesis and times the out one at a time and then total.
OpenStudy (amistre64):
just multiply the 2 together ...
OpenStudy (anonymous):
\[(2x)(2x)+(2x)(-3)+3(2x)+3(-3)\]
OpenStudy (anonymous):
4x^2-9
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (aravindg):
x= -3/2 or 3/2
OpenStudy (amistre64):
im old and tend to get lost in the f the o the i and the l so I just do it the simplest way I know how :)
2x+3
2x-3
---------
-6x-9
4x^2+6x
-----------
4x^2 + 0 -9
4x^2 - 9
OpenStudy (anonymous):
i hate math ugh ....
OpenStudy (anonymous):
i love how all of a sudden x equals something!
OpenStudy (anonymous):
you might could recognize that
\[(a+b)(a-b)=a^2-b^2\] foil or no foil. here you have
\[(2x+3)(2x-3)=(2x)^2-3^2=4x^2-9\]
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Well at least you're reaching out for help and more importantly explanation. Most folks here just wants answers.
OpenStudy (anonymous):
well i don't wanna havehelp all my life i like to be independent
OpenStudy (anonymous):
I prefer to just use normal distribution:
\[(2x+3)(2x-3)\]\[=2x(2x-3) + 3(2x-3)\]\[=4x^2 - 6x + 6x - 9\]\[=4x^2 - 9\]