If a baseball player hits a baseball from 4 feet off the ground with an initial velocity of 64 feet per second, how long will it take the baseball to hit the ground? Use the equation h = -16t^2 + 64t + 4

Question

anonymous · Answer

yeah like the ball really goes straight up and straight down.  these problems are ridiculous

anonymous · Answer

when it hits the ground the height will be zero so set 
$$-16t^2+64t+4=0$$ solve for t

amistre64 · Answer

divide out the common of -4 to get: 4t^2 -16t -1

and lets work it :)

4(t^2-4t+4) = 1 + 4(4)

(t-2)^2 = 17/4

t = 2 +- sqrt(17)/2 if i see it right

t = 2 + sqrt(17)/2 should do it

anonymous · Answer

i made the mistake!

anonymous · Answer

should be 
$$4t^2-16t-1=0$$ damn another wrong answer from me...

amistre64 · Answer

its the simple stuff that gets me all the time :)

anonymous · Answer

which i have now deleted!  i love revisionist history

anonymous · Answer

didn't get  you, it got me.  apparently i do not know how to divide 64 by 4 correctly

anonymous · Answer

Medal for "yeah like the ball really goes straight up and straight down. these problems are ridiculous"