Question

If a baseball player hits a baseball from 4 feet off the ground with an initial velocity of 64 feet per second, how long will it take the baseball to hit the ground? Use the equation h = -16t^2 + 64t + 4

Answer 1

yeah like the ball really goes straight up and straight down. these problems are ridiculous

Answer 2

when it hits the ground the height will be zero so set
\[-16t^2+64t+4=0\] solve for t

Answer 3

divide out the common of -4 to get: 4t^2 -16t -1

and lets work it :)

4(t^2-4t+4) = 1 + 4(4)

(t-2)^2 = 17/4

t = 2 +- sqrt(17)/2 if i see it right

t = 2 + sqrt(17)/2 should do it

Answer 4

i made the mistake!

Answer 5

should be
\[4t^2-16t-1=0\] damn another wrong answer from me...

Answer 6

its the simple stuff that gets me all the time :)

Answer 7

which i have now deleted! i love revisionist history

Answer 8

didn't get you, it got me. apparently i do not know how to divide 64 by 4 correctly

Answer 9

Medal for "yeah like the ball really goes straight up and straight down. these problems are ridiculous"