Question

Solve the following equations for x. Identify any extraneous solutions. Show all work.

√x+2+4=x

Answer 1

I really wish you'd use parens to show what was under the radical and what wasn't..

Answer 2

but there are no parens in this equation

Answer 3

\[\sqrt{x+2}+4=x\] is that your question

Answer 4

yes thats it

Answer 5

ok do it this way
\[\sqrt{x+2}=x-4\]
Then square both sidez\[(\sqrt{x+2})^{2}=(x-4)^{2}\]

Answer 6

\[(x+2)=x ^{2}-8x+16\]

Answer 7

\[x ^{2}-9x+14=0\]
\[(x-7)(x-2)=0\]
solution x=7,2But 2 doesn't work..... so only sol is x=7