Question

find all the zeros of f(x) = 3x^3-7x^2+6x-8

Answer 1

x = 1/6 (1-i sqrt(47))
x = 1/6 (1+i sqrt(47))
x = 2
Would you like an explanation?

Answer 2

RIght, real root is 2.

Answer 3

yes please

Answer 4

Factor
(x-2) (3 x^2-x+4)
x = 2
Then use the quadratic formula.

Answer 5

for 3x^2-x+4 use quadratic?

Answer 6

Yes

Answer 7

I see I see :D thank you.