Question

c^2-2c/6c-2 diveded by 2-c/1-3c?

Answer 1

step by step?

Answer 2

yes please

Answer 3

Well first off the answer is c/2 and I'll show you why

Answer 4

c^2 - 2c / 6c - 2 x 1 - 3c/2 -c
(numerators) [-c(2 - c)] x (1 -3c)
(denominators) [-2(1-3c)] x (2 -c)
now (2 - c) will be canceled and so will be (1 - 3c)
we'll be left with -c in numerator
and -2 in denominator
making the fraction -c/-2
or c/2

Answer 5

c^2 - 2c = c(c-2) = -c (-c + 2) = -c(2-c)
and 6c -2 = 2 (3c - 1) = -2 (-3c+1) = -2 (1-3c) and then the rest

Answer 6

\[\frac{c^2-2c}{6c-2} \div \frac{2-c}{1-3c} = \frac{c^2-2c}{6c-2} \times \frac{1-3c}{2-c}=\frac{c(c-2)}{2(3c-1)} \times \frac{3c -1}{c-2}=\frac{c}{2}\]