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If you had $10,000 and were investing it at 6% interest compounded continuously, how long would it take you to double your money, to the nearest tenth of a year?
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A = Pe^(rt) 20000 = 10000(e^.06x) x = 11.5 11.5 years.
SWEET! Thank you very much..
No Problem.
did you get the steps?
first of all doubling means doubling. it does not matter how much you start with, that is a red herring. just put \[2=e^{.06t}\] and solve for t
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ok?
then take the log to get \[\ln(2)=.06t\] and so \[t=\frac{\ln(2)}{.06}\]
ahhhh... yeah, ok.. cool!
then use a calculator
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