Question

help me pls..

Answer 1

now post your question

Answer 2

help:) f(x) = 3x-1
g(x)= 5/2x+7
h(x)= x^2+1
find:(fg/h)(-1)

Answer 3

-8 maybe

Answer 4

-2 not -8

Answer 5

how?

Answer 6

i got -4

Answer 7

just put -1 instead of x

Answer 8

ah I don't know -2 for me
I don't like these

Answer 9

then it would be (-4*9/2)/(2) =-9 na?

Answer 10

i dont know how to solve that kind of equation

Answer 11

its -2...
bcz,d functn, (fg/h)(x)= 5(3x-1)/(2x+7)(x^2+1)

nt put x=-1,n get d ansr..


m i r8??

Answer 12

how?

Answer 13

I get -2 as well.

Easiest way is to just evaluate f(-1), g(-1) and h(-1).

Then calculate\[\frac{f(-1)g(-1)}{h(-1)}\]

Answer 14

f(-1) = -4
g(-1) = 1
h(-1) = 2

(-4)(1)/(2) = -2

Answer 15

can you show me how? pls...

Answer 16

you understand how to calculate f(-1), right?

Answer 17

yah..

Answer 18

Well, (fg/h)(-1) is just saying to take the functions f, g, and h and create a new function that is f time g then divided by h.

Answer 19

and then eveaulate this new function at -1

Answer 20

but the results of the functions remain the same even when they are all combined, so if you evaluate them separately, then multiply/divide them, you'll get the same answer.

Answer 21

So unless they want you to tell them the actual function (fg/h)(x) and *then* calculate this at -1, it's best just to do them separately so you are dealing with numbers rather than variables.

Answer 22

oh... i get it

Answer 23

its simple yaar..

u got all d statements 4 d functns.. so,jst put (-1) in place of x..

f(x)= 3x-1
so,f(-1)=3*(-1)-1= -3-1=-4


g(x)=5/(2x+7)
g(-1)=5/(2(-1)+7= 5/-2+7= 5/5=1


h(x)=x^2+1=(-1)^2+1=1+1=2

thn,fg/h(-1)= (-4)*1/2= -2

Answer 24

good :)

Answer 25

thanks:)

Answer 26

np