Question

16^(-3/4)

Answer 1

\[1/8\]

Answer 2

\[16^\frac{-3}{4}=\frac{1}{16^\frac{3}{4}}=\frac{1}{2^3}=\frac{1}{8}\]

Answer 3

\[\Large 16^{-\frac{3}{4}}\]


\[\Large \frac{1}{16^{\frac{3}{4}}}\]


\[\Large \frac{1}{(\sqrt[4]{16})^3}\]


\[\Large \frac{1}{2^3}\]


\[\Large \frac{1}{8}\]


So \[\Large 16^{-\frac{3}{4}}=\frac{1}{8}\]