Question

Help ? Absolute value?

Answer 1

\[\left| x ^{2}-3x \right|=-4x+6\]

Answer 2

solve for both positive and negative cases when dealing with absolute value
\[x^{2}-3x = \pm (-4x+6)\]
Positive case:
\[x^{2}-3x = -4x+6\]
\[x^{2}+x-6 =0\]
\[(x+3)(x-2) = 0\]
\[x = -3, 2\]
Negative case:
\[x^{2}-3x = 4x-6\]
\[x^{2}-7x+6 =0\]
\[(x-6)(x-1) = 0\]
\[x = 1, 6\]