Question

Do you know how to do a problem such as 4^h-k/4h+k?

Answer 1

no . (4^h-k)/(4^h+k)

Answer 2

\[\frac{4^{h-k}}{4^{h+k}}\]
?

Answer 3

yes

Answer 4

\[\large \frac{4^{h-k}}{4^{h+k}}\]


\[\large 4^{(h-k)-(h+k)}\]


\[\large 4^{h-k-h-k}\]


\[\large 4^{-2k}\]


\[\large \frac{1}{4^{2k}}\]


\[\large \frac{1}{(4^2)^k}\]


\[\large \frac{1}{16^k}\]


So \[\large \frac{4^{h-k}}{4^{h+k}}=\frac{1}{16^k}\]

Answer 5

thank you so much