Question

Factor: 4x2 + 8x + 3
(2x + 1)(2x + 3)
(4x - 1)(x + 2)
(4x + 3)(x + 1)
prime

Answer 1

first one

Answer 2

Can someone help me Solve the equation by completing the square.
4x2 − 8x + 1 = 0

Answer 3

\[4(x^2-2x+\frac{1}{4}) \]\[4[(x-\frac{2}{2})^2-(\frac{2}{2})^2+\frac{1}{4}]\]\[4[ (x-1)^2-1+\frac{1}{4}]\]\[4[(x-1)^2-\frac{3}{4}] = 4(x-1)^2 -3\]