Question

Factor
w^3+ 64 =

Answer 1

w^3+64



(w)^3+(4)^3



(w+4)((w)^2-(w)(4)+(4)^2)



(w+4)(w^2-4w+16)



So w^3+64=(w+4)(w^2-4w+16)

Answer 2

This is using the sum of cubes formula.