Question

Three times the sum of 4 and a number y squared is the same as the difference of 14and the number y

Answer 1

Simplify

Answer 2

can you answer it

Answer 3

Yep - give me a sec :)

Answer 4

\[[3(4+y)]^2 = 14-y\]
\[(12+3y)^2 = 14-y\]
(12+3y)(12+3y) = 14-y

144 + 36y + 36y + 9y^2 = 14 - y

Answer 5

You then group the like terms, and solve the quadratic (I'll give you a second to try, while I'm writing out the rest)

Answer 6

130 + 73y + 9y^2 = 0

Answer 7

Have you been taught to use the quadratic equation to solve these kinds of questions?

Answer 8

i read it as
3(4+y^2)=14-y
12+3y^2=14-y
3y^2+y+12-14=0
3y^2+y-2=0

Answer 9

Ah OK! Then you are correct in your working out :) It depends on the punctuation in the question :)

Answer 10

(The answers for y are y = 2/3 , or y = -1, by the way :) )