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Find the equation of the horizontal line through (5,3)
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y = 5 ( Not sure if im right though xD)
How did you get that though?
um , bcos x=5
y=3
for all values of x, y=3
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ohh im wrong then xD
[here, jjwings22, y=-(5/3)+3
SalaamPerc can you show me how you got -5/3?
ok, a straight line graph is define by the th eequation... y=mx+c hop u understnd. where, m=gradient & c is the y-value when x=0, |dw:1314175903823:dw| therefore, y=mx+3, but the points are A(0,3) & B(5,0), Substitute B in the equation, which gives.. 0=m(5)+3, which gives m= -5/3, which is your gradient. Hence the equation y=-5/3m+3 is the equation of your graph, hop it helps ^_-
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