Question

What is the probability of rolling a number cube twice and getting an odd number each time?

Answer 1

1/4

Answer 2

1/2 the rolls are independent

Answer 3

\[\frac{1}{2}\times\frac{1}{2}\]

Answer 4

\[P(\text{odd on }1^{st} \text{ and }\text{odd on }2^{nd})\]

\[=P(\text{odd on }1^{st})P(\text{odd on }2^{nd})\]
\[=\frac{1}{2}\times\frac{1}{2}\]

Answer 5

1,3,5 are odd numbers that are on the cube

Answer 6

Thanks Zarkon. You got the answer, it was a simple calculation error. So it is (3/6)*(3/6) = 1/4