Question

how do you solve 3^x = 20 on a graphing calculator?

Answer 1

well answer is
\[x=\frac{\ln(20)}{\ln(3)}\] for sure

Answer 2

by change of base formula if you want to solve
\[b^x=A\] for x the answer is
\[x=\frac{\ln(A)}{\ln(b)}\]

Answer 3

thx!

Answer 4

in english, the log of the total divided by the log of the base. you can use
\[x=\frac{\log(A)}{\log(b)}\] to they both work

Answer 5

*too