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OpenStudy (anonymous):

how do you solve 3^x = 20 on a graphing calculator?

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OpenStudy (anonymous):

well answer is \[x=\frac{\ln(20)}{\ln(3)}\] for sure

OpenStudy (anonymous):

by change of base formula if you want to solve \[b^x=A\] for x the answer is \[x=\frac{\ln(A)}{\ln(b)}\]

OpenStudy (anonymous):

thx!

OpenStudy (anonymous):

in english, the log of the total divided by the log of the base. you can use \[x=\frac{\log(A)}{\log(b)}\] to they both work

OpenStudy (anonymous):

*too

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