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how do you solve 3^x = 20 on a graphing calculator?
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well answer is \[x=\frac{\ln(20)}{\ln(3)}\] for sure
by change of base formula if you want to solve \[b^x=A\] for x the answer is \[x=\frac{\ln(A)}{\ln(b)}\]
thx!
in english, the log of the total divided by the log of the base. you can use \[x=\frac{\log(A)}{\log(b)}\] to they both work
*too
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