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OpenStudy (anonymous):

how would i factor 4x^8-61x^4+225 so i get the awnser (2x^2+5)(2x^2-5)(x^2+3)(x^2-3)

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OpenStudy (anonymous):

i guess you have to first recognize \[4x^8-61x^4-225\] as a perfect square

OpenStudy (anonymous):

\[(a-b)^2=a^2-2ab+b^2\] and here \[a=2x^4, b=15, 2ab=60a^2\] so i assume you mean 60 and not 61 right?

OpenStudy (anonymous):

\[4x^8-60x^4+225\] maybe?

OpenStudy (anonymous):

i mean 61 lol

OpenStudy (anonymous):

oh then i don't know so let me shut up

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OpenStudy (anonymous):

trial and error, just like what you would do normally.

OpenStudy (anonymous):

thnaks

OpenStudy (anonymous):

i got it thanks both :D

OpenStudy (anonymous):

the answer is correct because if you give x a value, both give you the same answer...

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