Question

how would i factor 4x^8-61x^4+225 so i get the awnser (2x^2+5)(2x^2-5)(x^2+3)(x^2-3)

Answer 1

i guess you have to first recognize
\[4x^8-61x^4-225\] as a perfect square

Answer 2

\[(a-b)^2=a^2-2ab+b^2\] and here
\[a=2x^4, b=15, 2ab=60a^2\] so i assume you mean 60 and not 61 right?

Answer 3

\[4x^8-60x^4+225\] maybe?

Answer 4

i mean 61 lol

Answer 5

oh then i don't know so let me shut up

Answer 6

trial and error, just like what you would do normally.

Answer 7

thnaks

Answer 8

i got it thanks both :D

Answer 9

the answer is correct because if you give x a value, both give you the same answer...