Question

Attached below is a vector question. I'm having trouble grasping the concepts involved, but hopefully i have it figured out. Can someone that knows this stuff view the questions and perhaps verify my answers and/or steer me in the correct direction?

Answer 1

do you need help find component of the vector ? or unit vector?

Answer 2

i'll tell you where i'm at...u tell me if i'm on the right track?

Answer 3

a unit vector is akin to a "unit" circle, a "unit" anything = 1

Answer 4

sounds good

Answer 5

"unscale the vectors by dividing out the "length"; since length/length = 1

Answer 6

okay...i'll just work on the A vector....i got a length of 75 and an angle of 27 degrees....so if try to find Ax i use 75cos(27) to get 66.8?

Answer 7

i'm not following amistre

Answer 8

75cos(27) is right for Ax

Answer 9

before this afternoon i've never seen a vecotr in my life

Answer 10

then for Ay i should do the samething except 75sin(27) for 34.0?

Answer 11

x = 27 cos(t) ; y = 27sin(t)\[\]
A = <27 cos(t),27sin(t)\>[\]
unitA = <cos(t),sin(t)\>[\]right?

Answer 12

yep

Answer 13

ugh, i got lost in the nukbers; same concept tho i believe

Answer 14

okay...can you open the answer form attachment and tell me if that's all i put in the A vector slot?

Answer 15

yes, but they might want exact answer?

Answer 16

how would i go about exact answer?

Answer 17

75 cos(27) i, 75 sin(27)j

Answer 18

or is that my theta = artcan (ay/ax)?

Answer 19

let me try that again:\[\]
x = 75 cos(27) ; y = 75sin(27)\[\]
A = <75 cos(27),75 sin(27)>\[\]
unitA = <cos(27),sin(27)>\[\]

Answer 20

sadly this pellet is probably easy and i'm overcomplicating it huh?

Answer 21

yes, you got this

Answer 22

it is; you want to fit the vector into the unit circle

Answer 23

so the x ^ that rooftop on top of the x is what part?