Question

find the range of f(x)=3-√(2x+5)

Answer 1

biggest this can be is 3 because
\[\sqrt{2x+5}\geq 0\] so
\[-\sqrt{2x+5}\leq 0\] and therefore
\[3-\sqrt{2x+5}\leq 3\]

Answer 2

range is
\[(-\infty,3]\]