Mathematics
OpenStudy (anonymous):

find the range of f(x)=3-√(2x+5)

OpenStudy (anonymous):

biggest this can be is 3 because $\sqrt{2x+5}\geq 0$ so $-\sqrt{2x+5}\leq 0$ and therefore $3-\sqrt{2x+5}\leq 3$

OpenStudy (anonymous):

range is $(-\infty,3]$