Which set of three segments can form a triangle? 12, 30, 5 32, 19, 22 29, 35, 6 16, 31, 14

is it triangle?

which one forms a triangle?

:( i need posotive answers -.-

isnt it supposed to be equilateral triangle and not just a triangle

not likely...none of the choices has two equal lengths

Its IMPOSSIBLE :(

my best bet to go with is the third one

its second one 32, 19, 22

no. way. O.O yu figured it out! r yu sure?

I think I know of a way to solve this one. The law of cosines (valid for any triangle) says:\[c^2=a^2+b^2-2abcos \theta\]Now, lets try the first set and see what we get:\[900=169-2(5)(12)\cos \theta=169-120\cos \theta\]So,\[-6.09=\cos \theta\]Since cosine of an angle lies between -1 and 1, we have a contradiction. Thus 12, 30, 5 cannot form a triangle. Try this for the next three sets and see what you get.

i did the same equation

It's the second one. It works in law of cosines and it is correct.

the sum of the lengths of any two line segments must be greater than the length of the third line segment. 32+19=51>22 32+22=54>19 19+22=41>32 so,32, 19, 22

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