Mathematics
OpenStudy (anonymous):

Find the slope of the tangent line to the curve f(x)= x^2 + x - 1/x at x=-2

OpenStudy (anonymous):

You need to take the derivative of f(x) which represents you're curve. This will give you the slope as a function of x, and then you can plug in you're x value.

OpenStudy (anonymous):

that is $f'(x)=2x+1+\frac{1}{x^2}$ now plug in -2

OpenStudy (anonymous):

you get $f'(-2)=2\times -2+1+\frac{1}{(-2)^2}$

OpenStudy (anonymous):

i get $-\frac{11}{4}$ as the slope