Question

cube root 24x^8

Someone please help me :(

Answer 1

please help

Answer 2

man i messed that all up. lets do it the easy way

Answer 3

\[24=8\times 3\] and
\[\sqrt[3]{8}=2\] so a 2 comes out of the radical and a 3 stays in

Answer 4

lol ok easy sounds good

Answer 5

so the answer is 2?

Answer 6

3 goes in to 8 two times with a remainder of 2, so x^2 comes out and an x^2 stays in

Answer 7

the answer is
\[2x^2\sqrt[3]{3x^2}\]

Answer 8

i bet this is confusing you

Answer 9

not really i get it i just wanted to make sure I wasnt doing it wrong
thanks so much you are awesome!

Answer 10

yw
sorry i screwed up at first

Answer 11

do u think you can help me with the other question I had?

Answer 12

\[\sqrt[3]{24x^8}\], now see here .
\[\sqrt[3]{24x^8}\] now we have \[x^8=(x^2)^3\]
\[\sqrt[3]{24x^8}\] that is :
\[\sqrt[3]{3*2*2*2*(x^2)^3}\]
we have now
\[x^2*2\sqrt[3]{3}\]
hence the answer is \[x^2*2\sqrt[3]{3}\]
got it

Answer 13

u can ask more questions miizzt