Mathematics
OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

man i messed that all up. lets do it the easy way

OpenStudy (anonymous):

$24=8\times 3$ and $\sqrt[3]{8}=2$ so a 2 comes out of the radical and a 3 stays in

OpenStudy (anonymous):

lol ok easy sounds good

OpenStudy (anonymous):

OpenStudy (anonymous):

3 goes in to 8 two times with a remainder of 2, so x^2 comes out and an x^2 stays in

OpenStudy (anonymous):

the answer is $2x^2\sqrt[3]{3x^2}$

OpenStudy (anonymous):

i bet this is confusing you

OpenStudy (anonymous):

not really i get it i just wanted to make sure I wasnt doing it wrong thanks so much you are awesome!

OpenStudy (anonymous):

yw sorry i screwed up at first

OpenStudy (anonymous):

do u think you can help me with the other question I had?

OpenStudy (anonymous):

$\sqrt[3]{24x^8}$, now see here . $\sqrt[3]{24x^8}$ now we have $x^8=(x^2)^3$ $\sqrt[3]{24x^8}$ that is : $\sqrt[3]{3*2*2*2*(x^2)^3}$ we have now $x^2*2\sqrt[3]{3}$ hence the answer is $x^2*2\sqrt[3]{3}$ got it

OpenStudy (anonymous):

u can ask more questions miizzt