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OpenStudy (anonymous):

please help

OpenStudy (anonymous):

man i messed that all up. lets do it the easy way

OpenStudy (anonymous):

\[24=8\times 3\] and
\[\sqrt[3]{8}=2\] so a 2 comes out of the radical and a 3 stays in

OpenStudy (anonymous):

lol ok easy sounds good

OpenStudy (anonymous):

so the answer is 2?

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OpenStudy (anonymous):

3 goes in to 8 two times with a remainder of 2, so x^2 comes out and an x^2 stays in

OpenStudy (anonymous):

the answer is
\[2x^2\sqrt[3]{3x^2}\]

OpenStudy (anonymous):

i bet this is confusing you

OpenStudy (anonymous):

not really i get it i just wanted to make sure I wasnt doing it wrong
thanks so much you are awesome!

OpenStudy (anonymous):

yw
sorry i screwed up at first

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OpenStudy (anonymous):

do u think you can help me with the other question I had?

OpenStudy (anonymous):

\[\sqrt[3]{24x^8}\], now see here .
\[\sqrt[3]{24x^8}\] now we have \[x^8=(x^2)^3\]
\[\sqrt[3]{24x^8}\] that is :
\[\sqrt[3]{3*2*2*2*(x^2)^3}\]
we have now
\[x^2*2\sqrt[3]{3}\]
hence the answer is \[x^2*2\sqrt[3]{3}\]
got it