Mathematics 27 Online
OpenStudy (anonymous):

A car travels 22.7 m/s north for 30.4 minutes and then reverses direction and travels 27.5 m/s for 14.8 minutes. What is the car's total displacement?

OpenStudy (jwt625):

22.7*30.4*60-27.5*14.8*60=16984.8

OpenStudy (anonymous):

so i'm guessing multiple choice would be 1.70 x 10^4?

OpenStudy (anonymous):

u mind explaining this a bit for me? like where does the *60 come from?

OpenStudy (jwt625):

30.4minutes=30.4*60second

OpenStudy (anonymous):

alright i get that....would u verify an answer for me for another question?

OpenStudy (jwt625):

yes,I'll try

OpenStudy (anonymous):

okay.....an electron starting from rest and moving with constant acceleration travels 1.3 cm in 2.2 ms. What is the magnitude of this acceleration in km/s^2

OpenStudy (jwt625):

may be 650/121 km/s^2 ?if I didn't make a mistake.

OpenStudy (anonymous):

well i got 5.4

OpenStudy (anonymous):

which i believe is the same answer

OpenStudy (anonymous):

so that's good....thanks so much for your help

OpenStudy (jwt625):

my pleasure