Question

What is the approximate distance from (-2,3) to (4,1)?

5 units

6 units

8 units

9 units

Answer 1

6

Answer 2

6 units is the answer

Answer 3

\[distance=\sqrt{(x2-x1)^2+(y2-y1)^2}\]
\[\sqrt{(1-3)^2+(4-(-2)}\]
\[\sqrt{(-2)^2+(6)^2}\]
\[\sqrt{4+36}\]
\[\sqrt{40}\]
\[6.3=6units\]

Answer 4

one way to determine the distance is to create a rt triangle and use the pythag thrm on it

Answer 5

if we move from the lowest point up to the origin, we can get out lengths for x and y\[\]
(-2+2,3-3) to (4+2,1-3)\[\]
(0,0) to (6,-2)\[\]
this tells us x and y are 6 and -2, regardless of which is which; we can use them in the pythag

Answer 6

Thanks guyss :D i think this is my last question 4 a while :)

Answer 7

6^2 + 2^2 = d^2\[\]
36 + 4 = d^2\[\]
40 = d^2\[\]
which option when squared is closest to 40?

Answer 8

6 :D

Answer 9

id say 6 as well :) just to conform with the masses lol