Mathematics OpenStudy (anonymous):

What is the approximate distance from (-2,3) to (4,1)? 5 units 6 units 8 units 9 units OpenStudy (anonymous):

6 OpenStudy (anonymous): OpenStudy (anonymous):

$distance=\sqrt{(x2-x1)^2+(y2-y1)^2}$ $\sqrt{(1-3)^2+(4-(-2)}$ $\sqrt{(-2)^2+(6)^2}$ $\sqrt{4+36}$ $\sqrt{40}$ $6.3=6units$ OpenStudy (amistre64):

one way to determine the distance is to create a rt triangle and use the pythag thrm on it|dw:1314375146581:dw| OpenStudy (amistre64):

if we move from the lowest point up to the origin, we can get out lengths for x and y (-2+2,3-3) to (4+2,1-3) (0,0) to (6,-2) this tells us x and y are 6 and -2, regardless of which is which; we can use them in the pythag OpenStudy (amistre64):

|dw:1314375266048:dw| OpenStudy (anonymous):

Thanks guyss :D i think this is my last question 4 a while :) OpenStudy (amistre64):

6^2 + 2^2 = d^2 36 + 4 = d^2 40 = d^2 which option when squared is closest to 40? OpenStudy (anonymous):

6 :D OpenStudy (amistre64):

id say 6 as well :) just to conform with the masses lol

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