Factor the polynomial completely.

Question

anonymous · Answer

$$7x ^{3}-4x ^{2}+8x$$

anonymous · Answer

how did you get that? and aren't you supposed to find the 2 numbers after factoring (using the table or box method)

anonymous · Answer

ok

anonymous · Answer

$$7x^3-4x^2+8x=x(7x^2-4x+8)$$
7x^2-4x+8 has no real roots so, to continue factorising, we must use complex numbers.
We solve 7x^2-4x+8 using the quadratic formula to get x = 2/7 +- root(52)/7 i
Thus 
$$7x^3-4x^2+8x=x(x- \frac27 - \frac{\sqrt{52}}7 i)(x- \frac27 + \frac{\sqrt{52}}7 i)$$

anonymous · Answer

Which is quite ugly.  Stick to the real numbers.  It is neater

anonymous · Answer

so what would be the final answer?

anonymous · Answer

Have you worked with complex factorising before?

anonymous · Answer

If not, use the first line of my answer

anonymous · Answer

ok. and no i'm in algebra 2. thanks!

anonymous · Answer

Sure