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Help Please? Factor Completely: 2x2 − 32 Prime 2(x2 − 16) 2(x + 4)(x + 4) 2(x + 4)(x − 4)
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2(x + 4)(x − 4)
thanks... how do you figure that out?
ok first b/c u have 2 in common so put the two out
then u get 2(x^2-16)
then 2(x-4)(x+4)
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lol sry ik im not gd at explaining..
ok... i think i get it now... thanks!!! :)
2 is common so take it out \[2(x^2-16)\] \[x^2-y^2=(x+y)(x-y)\] so,\[2[(x)^2-(4)^2]=2(x+4)(x-4)\]
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