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Can someone remind me how to draw y=(2-|x|)(3+|x|). Thanks, badly out of practice dealing with modulus.
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\begin{align*}y=& (2-|x|)(3+|x|)\\=&6 - |x| - x^2\end{align*} It'll mostly look like a parabola opening downward. It just has a point at the vertex instead of the normal curve.
like this http://www.wolframalpha.com/input/?i=graph++y%3D%282- |x|%29%283%2B|x|%29
Polpak, we are in chat and want to know why u haven't fanned anybody....
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