Given f(x) and g(x), find all values of x for which f(x) = g(x). f(x)=x^2-6 and g(x)=10x-28 x=?? simplify, using radicals as needed.

Question

hero · Answer

x^2 - 6 = 10x - 28

solve for x

anonymous · Answer

$$x^2-10x=-22$$
$$(x-5)^2=-22+25=3$$
$$x-5=\pm\sqrt{3}$$
$$x=5\pm\sqrt{3}$$

anonymous · Answer

well, solving for x gives me (x^2+22)/10, but that's not the answer.
It tells me: "Set x^2-6 equal to 10x-28 and solve for x. Begin by completing the quare and then use the square root property to get all solutions of x." 
I don't know how to do that... :(

anonymous · Answer

Oh, thankssatellite :)

anonymous · Answer

you get what i wrote i hope