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OpenStudy (anonymous):
Where's the equation?
OpenStudy (anonymous):
-2a+1/3b-7a-b
OpenStudy (anonymous):
Collect like terms first
OpenStudy (anonymous):
oh ok thanks
OpenStudy (anonymous):
what do i do with the 1/3b and - b
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OpenStudy (anonymous):
What did you end up with?
OpenStudy (anonymous):
-9a and then idk what to do
OpenStudy (anonymous):
Well you can't do that cause the a terms are in diff places. One is in the numerator and the other is in the denominator
OpenStudy (anonymous):
so how do i work it?
OpenStudy (anonymous):
(-2a+1)/(3b-7a-b) = (-2a+1)/(2b-7a)
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OpenStudy (anonymous):
oohhh
OpenStudy (anonymous):
The have to be in the same place to collect the like terms
OpenStudy (anonymous):
i see thanks
OpenStudy (anonymous):
No problem :3
OpenStudy (anonymous):
i still dont get it its supposed to be one third b not 3b
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OpenStudy (anonymous):
If its one third b then this is how your expression should look like:\[2a + (\frac{1}{3}b) -7a-b\]
OpenStudy (anonymous):
Ohhhh that's what he meant ^
OpenStudy (anonymous):
You have to combine like terms and you have two terms here which are variables a and b. So you combine terms with a and you combine terms with b. The way you combine these variables which are like terms is by adding the coefficients which are the numbers in front of the variables
OpenStudy (anonymous):
Yeah I think so
OpenStudy (anonymous):
\[2a -7a = -5a\]
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OpenStudy (anonymous):
It's just simple math where you group the ones with the same variables together.
OpenStudy (anonymous):
\[\frac{1}{3} b - \frac{3}{3}b = -\frac{2}{3}b \]
OpenStudy (anonymous):
So the final answer is : \[-5a - \frac{2}{3}b \]
OpenStudy (anonymous):
its -2a
OpenStudy (anonymous):
thanks you helped alot !
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