Question

Correction Time.

Answer 1

I knw the answer is a Bit wrong.

Answer 2

\[y^\frac{4}{3}81^\frac{1}{3}y^\frac{5}{3}=y^\frac{3}{3}y^\frac{1}{3}(3^4)^\frac{1}{3}y^\frac{3}{3}y^\frac{2}{3}\]

Answer 3

\[y^1y^\frac{1}{3}3^\frac{4}{3}y^1y^\frac{2}{3}\]

Answer 4

in Radicals?

This is the second one, im cmming in a sec.

Answer 5

\[y \cdot y \cdot 3^\frac{3}{3}\cdot 3^\frac{1}{3} \cdot y^\frac{1}{3}y^\frac{2}{3}=y^2\cdot 3 \cdot 3^\frac{1}{3} y^\frac{1+2}{3}\]

Answer 6

\[3y^2\cdot 3^\frac{1}{3}\cdot y^1=3y^3 \sqrt[3]{3}\]

Answer 7

saifoo do you see that you just missed up on that one exponent right?

Answer 8

Yes, Right. Thanks! ^.^

Answer 9

Let me try the first one again, like u did, then i will let u know!

Answer 10

\[\sqrt[3]{a}(\sqrt[3]{3a^2}+\sqrt[3]{81a^2})=\sqrt[3]{a \cdot 3a^2}+\sqrt[3]{a \cdot 81a^2}\]
\[=\sqrt[3]{3a^3}+\sqrt[3]{81a^3}=\sqrt[3]{3}a+\sqrt[3]{3^4}a=\sqrt[3]{3}a+\sqrt[3]{3^3}\sqrt[3]{3}a=\sqrt[3]{3}a+3\sqrt[3]{3}a\]

Answer 11

WOW! u r simply grat.

Answer 12

Great*