Solve the system.

system of?

x -3z=8 2x+2y+9z=7 y+5=-2

y = -7

Let meme do that.

LOL

y+5z=-2

x -3z=8 2x+2y+9z=7 y+5z=-2

Should i jump in/

YUP :D You should xD

x = 5 y = 3 z = -1

is that simultaneous equation xD

and that is the answer.

LOL, no working out yur nice xD

how did you get that?

Meme, how'd u do that?

LOL, uswag was talking to you It will take me a while to work it out xD

i will take alot to work that out.

LOL , w8 did you use wolfram apha ?

Nah, that suck! i hate that website. I have CASIO fx-570ES.

ok, is there anyway someone can show me the steps? If i just wanted the answer I can look in the back of the book

LOL , wth is that ? can it solve questions xD

google that.

oh lols , its a calculator xD I have the CASIO fx-100AU xD

i have that too.

LOL

I have a casio fx-115es :)

While I'm a fan of calculators, (esp. Casio) can someone please show me how to do this step by step?

well that depends on what you know... you can solve it by substitution or with matrices

we've been working with matrices so far, but I'll take either form

x -3z=8 2x+2y+9z=7 y+5z=-2 x=3z+8 y=-5z-2 so middle equation becomes 2(3z+8)+2(-5z-2)+9z=7 solve for z then plug z into the two equations that are solved for x and y

x -3z=8 EQ (1) 2x+2y+9z=7 EQ(2) y+5z=-2 EQ(3) hi uswag, we can use matrix system here,or just by equating the system,and by substitution

x -3z=8 EQ1 2x+2y+9z=7 EQ2 2x+2y+9z=7 y+5z=-2 EQ(3) mult by 2, -( 2y+10z=-4) subtract from EQ2 --------------- 2x+0 -z=11 EQ4 x -3z=8 EQ1 mult by 2 -(2x -6z=16) subtract ----------------- 0 +5z=-5, z=-5/5=-1 ans sub this to EQ3 and EQ1 y+5(-1)=-2 EQ3 x-3z=8 EQ1 y-5=-2 x-3(-1)=8 y=-2+5=3 ans x+3=8 x=8-3=5 ans (x,y,z)=(5,3,-1) ans

hi thnx mimi.......

yw xD ,

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