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Mathematics
OpenStudy (anonymous):

Solve the system.

OpenStudy (saifoo.khan):

system of?

OpenStudy (anonymous):

x -3z=8 2x+2y+9z=7 y+5=-2

OpenStudy (mimi_x3):

y = -7

OpenStudy (saifoo.khan):

Let meme do that.

OpenStudy (mimi_x3):

LOL

OpenStudy (anonymous):

y+5z=-2

OpenStudy (anonymous):

x -3z=8 2x+2y+9z=7 y+5z=-2

OpenStudy (saifoo.khan):

Should i jump in/

OpenStudy (mimi_x3):

YUP :D You should xD

OpenStudy (saifoo.khan):

x = 5 y = 3 z = -1

OpenStudy (mimi_x3):

is that simultaneous equation xD

OpenStudy (saifoo.khan):

and that is the answer.

OpenStudy (mimi_x3):

LOL, no working out yur nice xD

OpenStudy (anonymous):

how did you get that?

OpenStudy (saifoo.khan):

Meme, how'd u do that?

OpenStudy (mimi_x3):

LOL, uswag was talking to you It will take me a while to work it out xD

OpenStudy (saifoo.khan):

i will take alot to work that out.

OpenStudy (mimi_x3):

LOL , w8 did you use wolfram apha ?

OpenStudy (saifoo.khan):

Nah, that suck! i hate that website. I have CASIO fx-570ES.

OpenStudy (anonymous):

ok, is there anyway someone can show me the steps? If i just wanted the answer I can look in the back of the book

OpenStudy (mimi_x3):

LOL , wth is that ? can it solve questions xD

OpenStudy (saifoo.khan):

google that.

OpenStudy (mimi_x3):

oh lols , its a calculator xD I have the CASIO fx-100AU xD

OpenStudy (saifoo.khan):

i have that too.

OpenStudy (mimi_x3):

LOL

OpenStudy (zarkon):

I have a casio fx-115es :)

OpenStudy (anonymous):

While I'm a fan of calculators, (esp. Casio) can someone please show me how to do this step by step?

OpenStudy (zarkon):

well that depends on what you know... you can solve it by substitution or with matrices

OpenStudy (anonymous):

we've been working with matrices so far, but I'll take either form

OpenStudy (zarkon):

x -3z=8 2x+2y+9z=7 y+5z=-2 x=3z+8 y=-5z-2 so middle equation becomes 2(3z+8)+2(-5z-2)+9z=7 solve for z then plug z into the two equations that are solved for x and y

OpenStudy (anonymous):

x -3z=8 EQ (1) 2x+2y+9z=7 EQ(2) y+5z=-2 EQ(3) hi uswag, we can use matrix system here,or just by equating the system,and by substitution

OpenStudy (anonymous):

x -3z=8 EQ1 2x+2y+9z=7 EQ2 2x+2y+9z=7 y+5z=-2 EQ(3) mult by 2, -( 2y+10z=-4) subtract from EQ2 --------------- 2x+0 -z=11 EQ4 x -3z=8 EQ1 mult by 2 -(2x -6z=16) subtract ----------------- 0 +5z=-5, z=-5/5=-1 ans sub this to EQ3 and EQ1 y+5(-1)=-2 EQ3 x-3z=8 EQ1 y-5=-2 x-3(-1)=8 y=-2+5=3 ans x+3=8 x=8-3=5 ans (x,y,z)=(5,3,-1) ans

OpenStudy (anonymous):

hi thnx mimi.......

OpenStudy (mimi_x3):

yw xD ,

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