Ask your own question, for FREE!
Mathematics 32 Online
OpenStudy (anonymous):

Obtain, in ascending powers of x, the first four terms in the expansion of (2-(x/2))^7. Hence find the value of (1.995)^7 correct to four decimal places. I have been able to do the first part, but am confused about the second part

OpenStudy (anonymous):

u in o levels doing add maths ???

OpenStudy (anonymous):

a binomial theorem question

OpenStudy (anonymous):

to do the second part 2-x/2=1.995 find x and put in place of x in the expansion required in the first part

OpenStudy (anonymous):

0.005 = 0.01/2

OpenStudy (anonymous):

yeah, IGCSE maths

OpenStudy (anonymous):

oh !!!

OpenStudy (anonymous):

i hope u get it

OpenStudy (anonymous):

the second part is quite simple. 1.995^7 can be rewritten in the expression given for the first part. all you have to do is, 1.995=2-x/2 find x. and then solve it using the expansion you got for the first part.

OpenStudy (anonymous):

so if my expansion is 128 - 2242x + 168x^2 - 70x^3.... then i just put 0.01 in place of x, and i should get it?

OpenStudy (anonymous):

yes u should get it

OpenStudy (anonymous):

that is correct.

OpenStudy (anonymous):

u r from .......

OpenStudy (anonymous):

india i guess

OpenStudy (anonymous):

yes :)

OpenStudy (anonymous):

oh!!!! i see

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Lilmunchin: Trump or Biden
47 minutes ago 66 Replies 3 Medals
ARTSMART: Art!
2 hours ago 5 Replies 5 Medals
Jasonisyours: What were the key causes of the French Revolution in 1789?
2 hours ago 3 Replies 5 Medals
PureSoulless: Why is the word "Pedophile" always censored in yt vids?
1 day ago 3 Replies 0 Medals
Jalli: What's 58x3634u00b07
1 day ago 6 Replies 3 Medals
arriya: who wanna play roblox
1 day ago 5 Replies 1 Medal
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!