please help me! ):
find the domain and range of y<=3x-2
\[y \le3x-2\]
find x and y int
how?
solve when x=0, y co-ordinate
so i plug in 0 as x and solve?
ok
i got \[y \le-2\]
yes so all y values are more than or equal to -2
actually nvm
sorry
dont copy that
its ok
sorry thinkin abt smthing else
ohh lol
domain and range are both real
all real numbers? how did you get that?
exactly, the domain and range of any linear equation (that's not vertical or horizontal) is the set of all real numbers This idea extends to linear inequalities as well.
yes
so it only isn't all real numbers if its a parabola? i think i'm getting it...
doesnt matter if they are an inequality or not
frankly i am not sure what this problem even means looks like x can be any number, as can y
okay. any idea how to graph it?
http://www.wolframalpha.com/input/?i=y%3C%3D3x-2 or t try http://my.hrw.com/math06_07/nsmedia/tools/Graph_Calculator/graphCalc.html
i would use second one for graphing it looks nice
thanks!
First, graph the line y=3x-2 now plug in the test point (0,0) ie plug in x = 0 and y = 0 to get y<=3x-2 0<=3(0)-2 0<=0-2 0<=-2 Since this inequality is false, this means that (0,0) is NOT in the shaded region. So shade the entire region that doesn't include (0,0)
ok
thank you everyone!
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