please help me! ):

find the domain and range of y<=3x-2

\[y \le3x-2\]

find x and y int

how?

solve when x=0, y co-ordinate

so i plug in 0 as x and solve?

ok

i got \[y \le-2\]

yes so all y values are more than or equal to -2

actually nvm

sorry

dont copy that

its ok

sorry thinkin abt smthing else

ohh lol

domain and range are both real

all real numbers? how did you get that?

exactly, the domain and range of any linear equation (that's not vertical or horizontal) is the set of all real numbers This idea extends to linear inequalities as well.

yes

so it only isn't all real numbers if its a parabola? i think i'm getting it...

doesnt matter if they are an inequality or not

frankly i am not sure what this problem even means looks like x can be any number, as can y

okay. any idea how to graph it?

http://www.wolframalpha.com/input/?i=y%3C%3D3x-2 or t try http://my.hrw.com/math06_07/nsmedia/tools/Graph_Calculator/graphCalc.html

i would use second one for graphing it looks nice

thanks!

First, graph the line y=3x-2 now plug in the test point (0,0) ie plug in x = 0 and y = 0 to get y<=3x-2 0<=3(0)-2 0<=0-2 0<=-2 Since this inequality is false, this means that (0,0) is NOT in the shaded region. So shade the entire region that doesn't include (0,0)

ok

thank you everyone!

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