Mathematics 84 Online
OpenStudy (anonymous):

OpenStudy (anonymous):

find the domain and range of y<=3x-2

OpenStudy (anonymous):

\[y \le3x-2\]

OpenStudy (anonymous):

find x and y int

OpenStudy (anonymous):

how?

OpenStudy (anonymous):

solve when x=0, y co-ordinate

OpenStudy (anonymous):

so i plug in 0 as x and solve?

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

i got \[y \le-2\]

OpenStudy (anonymous):

yes so all y values are more than or equal to -2

OpenStudy (anonymous):

actually nvm

OpenStudy (anonymous):

sorry

OpenStudy (anonymous):

dont copy that

OpenStudy (anonymous):

its ok

OpenStudy (anonymous):

sorry thinkin abt smthing else

OpenStudy (anonymous):

ohh lol

OpenStudy (anonymous):

domain and range are both real

OpenStudy (anonymous):

all real numbers? how did you get that?

jimthompson5910 (jim_thompson5910):

exactly, the domain and range of any linear equation (that's not vertical or horizontal) is the set of all real numbers This idea extends to linear inequalities as well.

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

so it only isn't all real numbers if its a parabola? i think i'm getting it...

OpenStudy (anonymous):

doesnt matter if they are an inequality or not

OpenStudy (anonymous):

frankly i am not sure what this problem even means looks like x can be any number, as can y

OpenStudy (anonymous):

okay. any idea how to graph it?

OpenStudy (anonymous):
OpenStudy (anonymous):

i would use second one for graphing it looks nice

OpenStudy (anonymous):

thanks!

jimthompson5910 (jim_thompson5910):

First, graph the line y=3x-2 now plug in the test point (0,0) ie plug in x = 0 and y = 0 to get y<=3x-2 0<=3(0)-2 0<=0-2 0<=-2 Since this inequality is false, this means that (0,0) is NOT in the shaded region. So shade the entire region that doesn't include (0,0)

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

thank you everyone!

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