A batter hits a baseball upward with an initial speed of 96 feet per second. After how many seconds does the ball hit the ground? Use the formula h = rt − 16t2 where h represents height in feet and r represents the initial speed.

Question

anonymous · Answer

$$h(t)=96t-16t^2$$

anonymous · Answer

when it hits the ground the height is 0 so set 
$$0=96t-16t^2$$ and solve for t

anonymous · Answer

$$0=6t-t^2$$
$$0=t(t-6)$$
$$t=6$$

amistre64 · Answer

to get a more exact answer, wed have to know the height of the ball when it was hit; a golfer on the other hand wed assume a height of 0

anonymous · Answer

apparently t = 0 too, which means that the baseball player is very very short

amistre64 · Answer

da plane... da plane

anonymous · Answer

attachment

anonymous · Answer

How did you get 0=6t-t^2?

anonymous · Answer

i have the same question

amistre64 · Answer

that depends on if you are using derivatives to calculate this, or just using properties of a parabola.