A batter hits a baseball upward with an initial speed of 96 feet per second. After how many seconds does the ball hit the ground? Use the formula h = rt − 16t2 where h represents height in feet and r represents the initial speed.
when it hits the ground the height is 0 so set \[0=96t-16t^2\] and solve for t
\[0=6t-t^2\] \[0=t(t-6)\] \[t=6\]
to get a more exact answer, wed have to know the height of the ball when it was hit; a golfer on the other hand wed assume a height of 0
apparently t = 0 too, which means that the baseball player is very very short
da plane... da plane
How did you get 0=6t-t^2?
i have the same question
that depends on if you are using derivatives to calculate this, or just using properties of a parabola.
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