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OpenStudy (anonymous):

A batter hits a baseball upward with an initial speed of 96 feet per second. After how many seconds does the ball hit the ground? Use the formula h = rt − 16t2 where h represents height in feet and r represents the initial speed.

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OpenStudy (anonymous):

\[h(t)=96t-16t^2\]

OpenStudy (anonymous):

when it hits the ground the height is 0 so set \[0=96t-16t^2\] and solve for t

OpenStudy (anonymous):

\[0=6t-t^2\] \[0=t(t-6)\] \[t=6\]

OpenStudy (amistre64):

to get a more exact answer, wed have to know the height of the ball when it was hit; a golfer on the other hand wed assume a height of 0

OpenStudy (anonymous):

apparently t = 0 too, which means that the baseball player is very very short

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OpenStudy (amistre64):

da plane... da plane

OpenStudy (anonymous):

OpenStudy (anonymous):

How did you get 0=6t-t^2?

OpenStudy (anonymous):

i have the same question

OpenStudy (amistre64):

that depends on if you are using derivatives to calculate this, or just using properties of a parabola.

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