Question

Find the quotient. Show all steps PLEASE.

4x^2 - y^2 / 2x + y

Answer 1

\[\large \frac{4x^2 - y^2}{2x + y}\]



\[\large \frac{(2x + y)(2x - y)}{2x + y}\]



\[\large \frac{\cancel{(2x + y)}(2x - y)}{\cancel{2x + y}}\]



\[\large 2x - y\]
So \[\large \frac{4x^2 - y^2}{2x + y}=2x - y\]

Answer 2

i love ur answers xD

Answer 3

thx

Answer 4

Jim is super fast!! Thanx Jim

Answer 5

np glad to help