Question

This question is about functions f(x) = x^2 - 13x - 30 and g(x) = -3x^3 + 7x. Calculate f(x) times g(x). Simplify the answer as much as possible.

Answer 1

\[f\cdot g=(x^2-13x-30)(-3x^3+7x)=x^2(-3x^3+7x)-13x(-3x^3+7x)-30(-3x^3+7x)\]

Answer 2

now apply the distributive property for each of the three terms

Answer 3

and then combine like terms

Answer 4

a little long there myininaya

Answer 5

and woolah!

Answer 6

\[\large (f(x))(g(x))\]


\[\large (x^2 - 13x - 30)(-3x^3 + 7x)\]


\[\large (-3x^3 + 7x)(x^2 - 13x - 30)\]


\[\large -3x^3(x^2 - 13x - 30)+7x(x^2 - 13x - 30)\]


\[\large -3x^5 +39x^4+ 90x^3+7x^3 -91x^2 -210x\]


\[\large -3x^5 +39x^4+ 97x^3 -91x^2 -210x\]
So \[\large (x^2 - 13x - 30)(-3x^3 + 7x)=-3x^5 +39x^4+ 97x^3 -91x^2 -210x\]

Answer 7

is it cut off?
it doesn't show me any cutoffness

Answer 8

maybe it is my browser. i see as far as -13x

Answer 9

:(

Answer 10

ok well just look at what jim has
anything he ever does is perfect

Answer 11

I find it better to expand (A+B+C)(D+E) to D(A+B+C)+E(A+B+C)

instead of A(D+E)+B(D+E)+C(D+E) since it's shorter

but you'll get the same answer either way