0 to the fifth power is zero right?
yes
0^n = 0
0^0 is indeterminate form
when n is not 0, i should say :)
thanks
:)
lots of interesting historical debate on \[0^0\]
thats why i was confused
0^5 ¨= 0*0*0*0*0 = 0
interesting being a relative term i guess. http://mathforum.org/dr.math/faq/faq.0.to.0.power.html
im very new to algebra \[\sqrt[3]{?-125}\] so thats not a real number?
yes don't get cube roots confused with square roots
\[\sqrt[3]{-125}=-5\] because \[(-5)^3=-125\]
you can take the cube root of a negative number. you just cannot take a square root, fourth root, or any even root of a negative number and get a real number back
The two interesting cases of 0^n are: \[0^0;0^{\infty}\] Both of those are indeterminate. But as long as n is non zero and finite then 0^n=0.
But why are they interesting?
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