I don't know how to find the domain and range for y=4x-3 and identify any if the equation define functions

D: all real values of x

wooooow. meme to the rescue.

LOL

What u mean by all real values of x how did u know that?

The domain and range of any line (that is not vertical or horizontal) is the set of all real numbers.

Well, for straight lines domain is all real values of x

Then how about if the question will be y=-2(x-3)sequerd+4

what's sequerd ?

sorry miss spelled I mean squared

\[\textrm{Domain is the set of all real numbers}\] \[\textrm{Range is }(-\infty,4]\]

But I want to know how to do it not to just know the answer

How come it's x^4 when it's (x-3)^2

I don't know how to do it!!!! I'm waiting for someone to reply

The domain of any quadratic is the set of all real numbers.

The range of the quadratic \[\large y=a(x-h)^2+k\] is \[\large (-\infty, k]\] if \[\large a <0\] -------------------------- The range of the quadratic \[\large y=a(x-h)^2+k\] is \[\large [k,\infty)\] if \[\large a >0\]

In this case, a=-2 and k=4, so you pick the first option described above.

Oh, ok thank u for the help. now I got it

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